32x^2+33x+1=0

Solution for 32x^2+33x+1=0 equation:

32x^2+33x+1=0

a = 32; b = 33; c = +1;
Δ = b2-4ac
Δ = 332-4·32·1
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-31}{2*32}=\frac{-64}{64}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+31}{2*32}=\frac{-2}{64}
=-1/32
$